int {frac{{{e^{5log x}} - {e^{4log x}}}}{{{e^ | vedclass

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(C) हम जानते हैं कि ${e^{\log f(x)}} = f(x)$.अतः,समाकलन इस प्रकार होगा:$\int {\frac{{{x^5} - {x^4}}}{{{x^3} - {x^2}}}\,dx}$$= \int {\frac{{{x^4}(x - 1

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$\frac{{{x^3}}}{3} + c$

Vedclass · Answer

(C) हम जानते हैं कि ${e^{\log f(x)}} = f(x)$.अतः,समाकलन इस प्रकार होगा:$\int {\frac{{{x^5} - {x^4}}}{{{x^3} - {x^2}}}\,dx}$$= \int {\frac{{{x^4}(x - 1)}}{{{x^2}(x - 1)}}\,dx}$$= \int {{x^2}\,dx}$$= \frac{{{x^3}}}{3} + c$.

$\int {\frac{{{e^{5\log x}} - {e^{4\log x}}}}{{{e^{3\log x}} - {e^{2\log x}}}}\;dx} = $

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