(B) We know that the derivative of $\sec x$ with respect to $x$ is given by: $\frac{d}{dx}(\sec x) = \sec x \tan x$ By the definition of the indefinit

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(B) We know that the derivative of $\sec x$ with respect to $x$ is given by: $\frac{d}{dx}(\sec x) = \sec x \tan x$ By the definition of the indefinite integral (antiderivative),if $\frac{d}{dx}(F(x)) = f(x)$,then $\int f(x) \, dx = F(x) + c$. Therefore,$\int \sec x \tan x \, dx = \sec x + c$. Thus,the correct option is $B$.