A 0.1 M solution of a solute has a water pot | vedclass

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(A) The water potential $(\Psi_w)$ of a solution is primarily determined by the solute potential $(\Psi_s)$, as $\Psi_w = \Psi_s + \Psi_p$. For a non-

Vedclass · Accepted Answer

$-2.3 \ 	ext{bars}$

Vedclass · Answer

(A) The water potential $(\Psi_w)$ of a solution is primarily determined by the solute potential $(\Psi_s)$, as $\Psi_w = \Psi_s + \Psi_p$. For a non-pressurized solution, $\Psi_p = 0$, so $\Psi_w = \Psi_s$.Solute potential $(\Psi_s)$ is calculated as $-iCRT$. For a $0.1 \ M$ sucrose solution, the osmotic pressure $(OP)$ is approximately $2.3 \ 	ext{bars}$.Since solute potential is the negative of osmotic pressure $(\Psi_s = -OP)$, the value is $-2.3 \ 	ext{bars}$.Therefore, the water potential of a $0.1 \ M$ solution is $-2.3 \ 	ext{bars}$.

$A$ $0.1 \ M$ solution of a solute has a water potential of:

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