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Question

(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$

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Coefficient of viscosity

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(D) The unit of pressure is $Pascal$ $(Pa)$,which has the dimensional formula $[M L^{-1} T^{-2}]$.Therefore,the dimensional formula of $Pascal-second$ $(Pa \cdot s)$ is $[M L^{-1} T^{-2}] 	imes [T] = [M L^{-1} T^{-1}]$.The coefficient of viscosity $(\eta)$ is defined by the formula:$\eta = \frac{F}{A (\Delta v / \Delta z)}$where $F$ is force,$A$ is area,and $\frac{\Delta v}{\Delta z}$ is the velocity gradient.The dimensions of $\eta$ are:$	ext{Dimensions of } \eta = \frac{[M L T^{-2}]}{[L^2] [T^{-1}]} = [M L^{-1} T^{-1}]$.Since the dimensions of $Pascal-second$ match the dimensions of the coefficient of viscosity,the correct option is $D$.

List $I$ (Physical Quantity)	List $II$ (Dimensional Formula)
$(A)$ Pressure gradient	$(I)$ $[M^0 L^2 T^{-2}]$
$(B)$ Energy density	$(II)$ $[M^1 L^{-1} T^{-2}]$
$(C)$ Electric Field	$(III)$ $[M^1 L^{-2} T^{-2}]$
$(D)$ Latent heat	$(IV)$ $[M^1 L^1 T^{-3} A^{-1}]$

$Pascal-Second$ has the dimension of:

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