Compared to C_3 plants,how many additional AT | vedclass

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(D) In $C_3$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_4$ plants,an additi

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Twelve

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(D) In $C_3$ plants,the synthesis of one molecule of glucose $(C_6H_{12}O_6)$ requires $18$ $ATP$ and $12$ $NADPH$ molecules.In $C_4$ plants,an additional $6$ $ATP$ molecules are required for the regeneration of phosphoenolpyruvate $(PEP)$ in the mesophyll cells,totaling $30$ $ATP$ $(18 + 12 = 30)$ and $12$ $NADPH$ molecules.Therefore,the additional $ATP$ requirement for $C_4$ plants compared to $C_3$ plants is $30 - 18 = 12$ $ATP$ molecules per hexose molecule.

Compared to $C_3$ plants,how many additional $ATP$ molecules are required to produce one molecule of hexose in $C_4$ plants?

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