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(A) In one turn of the Krebs cycle ($TCA$ cycle), the following reduced coenzymes are produced:$1$. $3$ molecules of $NADH + H^+$$2$. $1$ molecule of

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$11$

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(A) In one turn of the Krebs cycle ($TCA$ cycle), the following reduced coenzymes are produced:$1$. $3$ molecules of $NADH + H^+$$2$. $1$ molecule of $FADH_2$$3$. $1$ molecule of $GTP$ (which is equivalent to $1$ $ATP$)During the electron transport system $(ETS)$:- Each $NADH + H^+$ produces $3$ $ATP$ molecules.- Each $FADH_2$ produces $2$ $ATP$ molecules.Calculation:- $3$ $NADH 	imes 3 = 9$ $ATP$- $1$ $FADH_2 	imes 2 = 2$ $ATP$- Total $ATP$ from $ETS$ = $9 + 2 = 11$ $ATP$.Therefore, the number of $ATP$ molecules produced through the electron transport system from the intermediates of a single turn of the Krebs cycle is $11$.

The number of $ATP$ molecules produced through the electron transport system from the intermediates of a single turn of the Krebs cycle is ......... .

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