What is the number of oxygen molecules requir | vedclass

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(A) The aerobic oxidation of one molecule of pyruvate involves the link reaction and the Krebs cycle.
$1$. Link reaction: $1$ Pyruvate + $1$ CoA + $1

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$2$

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(A) The aerobic oxidation of one molecule of pyruvate involves the link reaction and the Krebs cycle.
$1$. Link reaction: $1$ Pyruvate + $1$ CoA + $1$ $NAD^+$ $ightarrow$ $1$ Acetyl-CoA + $1$ $NADH$ + $1$ $CO_2$.
$2$. Krebs cycle: $1$ Acetyl-CoA + $3$ $NAD^+$ + $1$ $FAD$ + $1$ $GDP$ + $1$ $\Pi$ + $2$ $H_2O$ $ightarrow$ $2$ $CO_2$ + $3$ $NADH$ + $1$ $FADH_2$ + $1$ $GTP$ + $1$ CoA.
Total $NADH$ produced = $1$ (link) + $3$ (Krebs) = $4$ $NADH$.
Total $FADH_2$ produced = $1$ $FADH_2$.
In the Electron Transport System $(ETS)$,the oxidation of $1$ $NADH$ requires $0.5$ $O_2$ and $1$ $FADH_2$ requires $0.5$ $O_2$.
Total $O_2$ required = $(4 	imes 0.5) + (1 	imes 0.5) = 2 + 0.5 = 2.5$ molecules of $O_2$ per pyruvate.
The balanced equation for the complete oxidation of pyruvate is: $CH_3COCOOH + 2.5 O_2 ightarrow 3 CO_2 + 2 H_2O$. Thus,$2.5$ molecules of $O_2$ are required.

What is the number of oxygen molecules required for the aerobic oxidation of one molecule of pyruvate (in $.5$)?

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