If a normal DNA molecule replicates in an N^{ | vedclass

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(C) The replication of $DNA$ is semi-conservative.In the $1^{st}$ generation,all $DNA$ molecules are hybrid $(N^{14}-N^{15})$.In the $2^{nd}$ generati

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(C) The replication of $DNA$ is semi-conservative.In the $1^{st}$ generation,all $DNA$ molecules are hybrid $(N^{14}-N^{15})$.In the $2^{nd}$ generation,there are $2$ hybrid and $2$ heavy $(N^{15}-N^{15})$ molecules.In subsequent generations,the number of hybrid molecules remains constant at $2$,while the number of heavy molecules increases.Since the medium is $N^{15}$ (heavy),no new light $(N^{14})$ $DNA$ strands are formed after the first replication.Therefore,after the $1^{st}$ generation,the percentage of light $DNA$ is $0\%$.

If a normal $DNA$ molecule replicates in an $N^{15}$ medium for consecutive generations,what is the percentage of light $DNA$ in the $4^{th}$ generation (in $\%$)?

Similar Questions

In a nucleus,the number of ribonucleoside triphosphates is $10$ times the number of deoxyribonucleoside triphosphates,but only deoxyribonucleotides are added during $DNA$ replication. Suggest a mechanism.

On which template strand of $DNA$ is the new strand synthesized discontinuously?

Who discovered "Reverse transcription"?

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