During the formation of the dimer N_2O_4 from | vedclass

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(B) $NO_2$ is an odd-electron molecule with a paramagnetic character due to the unpaired electron on the nitrogen atom. When two $NO_2$ molecules dime

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$A$ weak $N-N$ bond is formed and all four $N-O$ bonds become equal.

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(B) $NO_2$ is an odd-electron molecule with a paramagnetic character due to the unpaired electron on the nitrogen atom. When two $NO_2$ molecules dimerize to form $N_2O_4$,the unpaired electrons on the nitrogen atoms pair up to form a weak $N-N$ single bond. In the $N_2O_4$ structure,the $N-N$ bond is relatively long and weak. Due to resonance,the four $N-O$ bonds in $N_2O_4$ become equivalent in length,each having a bond order of $1.5$.

During the formation of the dimer $N_2O_4$ from two molecules of $NO_2$,the odd electron on the nitrogen atom of each $NO_2$ molecule pairs up. What is the resulting structure?

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