(C) The molecule $SF_3Cl_3$ is a derivative of $SF_6$. In $SF_6$,the sulfur atom is $sp^3d^2$ hybridized,resulting in an octahedral geometry. When thr

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(C) The molecule $SF_3Cl_3$ is a derivative of $SF_6$. In $SF_6$,the sulfur atom is $sp^3d^2$ hybridized,resulting in an octahedral geometry. When three fluorine atoms are replaced by three chlorine atoms,the octahedral arrangement is maintained. Therefore,the shape of the $SF_3Cl_3$ molecule is octahedral.