(C) The initial charge on the first capacitor is $Q_1 = C_1 V_1 = 2\,\mu F \times 200\;V = 400\,\mu C$.When the second capacitor $C_2$ (initially unch

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(C) The initial charge on the first capacitor is $Q_1 = C_1 V_1 = 2\,\mu F \times 200\;V = 400\,\mu C$.When the second capacitor $C_2$ (initially uncharged,$V_2 = 0$) is connected in parallel,the total charge remains conserved.The common potential $V$ is given by the formula: $V = \frac{C_1 V_1 + C_2 V_2}{C_1 + C_2}$.Substituting the given values: $20 = \frac{2 \times 200 + C_2 \times 0}{2 + C_2}$.$20 = \frac{400}{2 + C_2}$.$2 + C_2 = \frac{400}{20} = 20$.$C_2 = 20 - 2 = 18\,\mu F$.

Class 12 Physics Electric Potential and Capacitance Sharing of Charge in Capacitor Circuit

Medium

$A$ $2\,\mu F$ capacitor has a potential difference of $200\;V$ across its terminals. It is disconnected from the battery and then another uncharged capacitor is connected in parallel to it. If the potential difference becomes $20\;V$,the capacitance of the second capacitor is.......$\mu F$.

A
$2$
B
$4$
C
$18$
D
$10$

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Class 12 Questions

Class 12

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Electric Potential and Capacitance

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Sharing of Charge in Capacitor Circuit

$A$ capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity. The potential difference across the combination becomes $V$. The unknown capacitance is

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$A$ body of capacity $4\,\mu F$ is charged to $80\,V$ and another body of capacity $6\,\mu F$ is charged to $30\,V$. When they are connected,the energy lost by the $4\,\mu F$ capacitor is.......$mJ$.

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$A$ $3\ \mu F$ capacitor is charged to a potential of $300\ V$ and a $2\ \mu F$ capacitor is charged to $200\ V$. They are then connected in parallel with plates of opposite polarity joined together. What is the amount of charge (in $\mu C$) that flows through the connecting wires?

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Two capacitors of $1\,\mu F$ and $2\,\mu F$ are charged to $1200\,V$. If they are connected in parallel such that the positive plate of one is connected to the negative plate of the other,what will be the new charge on each capacitor?

Medium

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Two capacitors of values $C_1$ and $C_2$ are charged to potentials $V_1$ and $V_2$ respectively. When they are connected in parallel,there will be no change in which of the following?

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$A$ $2\,\mu F$ capacitor has a potential difference of $200\;V$ across its terminals. It is disconnected from the battery and then another uncharged capacitor is connected in parallel to it. If the potential difference becomes $20\;V$,the capacitance of the second capacitor is.......$\mu F$.

Similar Questions

$A$ capacitor of capacitance $C$ is charged to a potential difference $V_0$. The charging battery is removed and the capacitor is now connected to an uncharged capacitor of unknown capacity. The potential difference across the combination becomes $V$. The unknown capacitance is

$A$ body of capacity $4\,\mu F$ is charged to $80\,V$ and another body of capacity $6\,\mu F$ is charged to $30\,V$. When they are connected,the energy lost by the $4\,\mu F$ capacitor is.......$mJ$.

$A$ $3\ \mu F$ capacitor is charged to a potential of $300\ V$ and a $2\ \mu F$ capacitor is charged to $200\ V$. They are then connected in parallel with plates of opposite polarity joined together. What is the amount of charge (in $\mu C$) that flows through the connecting wires?

Two capacitors of $1\,\mu F$ and $2\,\mu F$ are charged to $1200\,V$. If they are connected in parallel such that the positive plate of one is connected to the negative plate of the other,what will be the new charge on each capacitor?

Two capacitors of values $C_1$ and $C_2$ are charged to potentials $V_1$ and $V_2$ respectively. When they are connected in parallel,there will be no change in which of the following?

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