In a random mating population,the frequency o | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ i

Vedclass · Accepted Answer

$0.09$

Vedclass · Answer

(C) According to the Hardy-Weinberg principle,the sum of allele frequencies is $p + q = 1$,where $p$ is the frequency of the dominant allele and $q$ is the frequency of the recessive allele.Given that the frequency of the dominant allele $p = 0.7$,we can calculate the frequency of the recessive allele $q$ as follows:$q = 1 - p = 1 - 0.7 = 0.3$.The frequency of the recessive phenotype in a population is represented by the Hardy-Weinberg equation term $q^2$ (homozygous recessive genotype).Therefore,the frequency of the recessive phenotype = $q^2 = (0.3)^2 = 0.09$.

In a random mating population,the frequency of the dominant allele is $0.7$. What will be the frequency of the recessive phenotype?

Similar Questions

Recessive alleles are not lost from the gene pool. This is known as:

In a population that is not evolving, which of the following can cause a change in allele frequencies in a specific direction?

Explain the Hardy-Weinberg principle using an algebraic equation.

In a population of $800$ rabbits showing Hardy-Weinberg equilibrium,the frequency of recessive individuals was $0.16$. What is the frequency of heterozygous individuals?

If the values of the mean and median for a specific trait in a population are equal,what is the most likely outcome?

Vedclass Test Series

Exam Paper Generator

Online Exam Module