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(C) Colorblindness is an $X$-linked recessive trait. Let $X^c$ represent the allele for colorblindness and $X$ represent the normal allele. The man is

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One son and one daughter

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(C) Colorblindness is an $X$-linked recessive trait. Let $X^c$ represent the allele for colorblindness and $X$ represent the normal allele. The man is colorblind,so his genotype is $X^c Y$. The woman is normal but her father was colorblind,meaning she inherited the $X^c$ allele from him. Thus,her genotype is $X X^c$. Crossing $X^c Y$ (man) with $X X^c$ (woman): Offspring genotypes: $X X^c$ (carrier daughter),$X^c X^c$ (colorblind daughter),$X Y$ (normal son),$X^c Y$ (colorblind son). Statistically,there is a $50\%$ chance for each child to be colorblind regardless of gender. However,in the context of this specific cross,one son and one daughter are expected to be colorblind.

$A$ colorblind man marries a normal woman whose father was colorblind. Among their two sons and two daughters,who will be colorblind?

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