What will be the ratio of heterozygous,homozy | vedclass

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(A) Color blindness is an $X$-linked recessive disorder. Let $X^C$ be the allele for normal vision and $X^c$ be the allele for color blindness.The gen

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$1:1:2$

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(A) Color blindness is an $X$-linked recessive disorder. Let $X^C$ be the allele for normal vision and $X^c$ be the allele for color blindness.The genotype of a color-blind husband is $X^cY$ (hemizygous).The genotype of a carrier wife is $X^CX^c$ (heterozygous).Crossing $X^cY 	imes X^CX^c$ results in the following offspring:$1$. $X^CX^c$ (Carrier daughter - heterozygous)$2$. $X^cX^c$ (Color-blind daughter - homozygous recessive)$3$. $X^CY$ (Normal son - hemizygous)$4$. $X^cY$ (Color-blind son - hemizygous)Summary of genotypes:- Heterozygous: $1$ $(X^CX^c)$- Homozygous: $1$ $(X^cX^c)$- Hemizygous: $2$ ($X^CY$ and $X^cY$)The ratio is $1:1:2$.

What will be the ratio of heterozygous,homozygous,and hemizygous color blindness in the offspring of a color-blind husband and a carrier wife?

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