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(C) In a dihybrid cross between $AABB$ and $aabb$,the $F_1$ generation produces $AaBb$ individuals.When $F_1$ individuals $(AaBb)$ are self-crossed,th

Vedclass · Accepted Answer

$1:2:2:1$

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(C) In a dihybrid cross between $AABB$ and $aabb$,the $F_1$ generation produces $AaBb$ individuals.When $F_1$ individuals $(AaBb)$ are self-crossed,the $F_2$ generation follows the Mendelian dihybrid ratio of $9:3:3:1$ (phenotypic).However,the question asks for the specific genotypic ratio of the four given genotypes: $AABB, AABb, aaBb,$ and $aabb$.In the $F_2$ Punnett square,the frequencies are:$AABB = 1/16$$AABb = 2/16$$aaBb = 2/16$$aabb = 1/16$Thus,the ratio of $AABB : AABb : aaBb : aabb$ is $1:2:2:1$.

In a dihybrid cross between $AABB$ and $aabb$,the ratio of $AABB, AABb, aaBb,$ and $aabb$ in the $F_2$ generation is:

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