In a cross between plants with red and white | vedclass

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(A) $1$. The $F_2$ ratio of $60:20$ simplifies to $3:1$. This indicates a Mendelian monohybrid cross where red is dominant over white.$2$. Let $R$ be

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$72:24$

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(A) $1$. The $F_2$ ratio of $60:20$ simplifies to $3:1$. This indicates a Mendelian monohybrid cross where red is dominant over white.$2$. Let $R$ be the allele for red flowers and $r$ be the allele for white flowers.$3$. The heterozygous red-flowered plant has the genotype $Rr$.$4$. Self-pollination of $Rr$ $(Rr 	imes Rr)$ results in the following Punnett square: $RR, Rr, Rr, rr$.$5$. The phenotypic ratio is $3$ red $(RR, Rr, Rr)$ to $1$ white $(rr)$,which is $3:1$.$6$. Among the options provided,$72:24$ simplifies to $3:1$ $(72/24 = 3)$,which matches the expected phenotypic ratio.

In a cross between plants with red and white flowers,the ratio of red to white flowered plants in the $F_2$ generation was $60:20$. If a heterozygous red-flowered plant is self-pollinated,what will be the ratio of the progeny?

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