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(D) $1$. The total number of plants produced is $140 + 40 = 180$ (Note: The problem mentions $200$ seeds,but $180$ germinated). $2$. The ratio of tall

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$Tt$ and $tt$

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(D) $1$. The total number of plants produced is $140 + 40 = 180$ (Note: The problem mentions $200$ seeds,but $180$ germinated). $2$. The ratio of tall to dwarf plants is $140:40$,which simplifies to $7:2$ or approximately $3:1$. $3$. $A$ phenotypic ratio of $3:1$ in the $F_1$ generation is characteristic of a monohybrid cross between two heterozygous parents $(Tt 	imes Tt)$. $4$. In a cross between two heterozygous parents $(Tt 	imes Tt)$,the expected genotypic ratio is $1TT : 2Tt : 1tt$. $5$. Since both tall ($TT$ and $Tt$) and dwarf $(tt)$ plants are produced,the parent must be heterozygous $(Tt)$ for the height trait.

From a single cob of maize,a farmer planted $200$ seeds which produced $140$ tall and $40$ dwarf plants. The genotype of the parent is primarily....

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