If a color-blind woman marries a normal man,t | vedclass

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(B) Color blindness is an $X$-linked recessive disorder. Let $X^c$ represent the allele for color blindness and $X$ represent the normal allele. The g

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All daughters normal and all sons color-blind

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(B) Color blindness is an $X$-linked recessive disorder. Let $X^c$ represent the allele for color blindness and $X$ represent the normal allele. The genotype of a color-blind woman is $X^cX^c$. The genotype of a normal man is $XY$. When these two cross: $X^cX^c 	imes XY ightarrow X^cX$ (carrier daughter),$X^cY$ (color-blind son). Since the woman passes one $X^c$ to all her children,all sons will receive the $X^c$ chromosome from their mother and the $Y$ chromosome from their father,making them color-blind $(X^cY)$. All daughters will receive one $X^c$ from their mother and one $X$ from their father,making them carriers (phenotypically normal) $(X^cX)$. Therefore,all daughters are normal (carriers) and all sons are color-blind.

If a color-blind woman marries a normal man,their offspring will be:

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