The E.C.E. of Cu and Ag are 7 times 10^{-6} | vedclass

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(C) According to Faraday's second law of electrolysis,the mass of substances deposited by the same quantity of electricity is proportional to their ch

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$2.4$

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(C) According to Faraday's second law of electrolysis,the mass of substances deposited by the same quantity of electricity is proportional to their chemical equivalents or $E.C.E.$ values.$\frac{m_{Cu}}{m_{Ag}} = \frac{Z_{Cu}}{Z_{Ag}}$Given: $m_{Cu} = 14 \ g$,$Z_{Cu} = 7 	imes 10^{-6}$,$Z_{Ag} = 1.2 	imes 10^{-6}$.$m_{Ag} = \frac{m_{Cu} 	imes Z_{Ag}}{Z_{Cu}}$$m_{Ag} = \frac{14 	imes 1.2 	imes 10^{-6}}{7 	imes 10^{-6}}$$m_{Ag} = 2 	imes 1.2 = 2.4 \ g$.

The $E.C.E.$ of $Cu$ and $Ag$ are $7 \times 10^{-6} \ g/C$ and $1.2 \times 10^{-6} \ g/C$ respectively. If a certain current deposits $14 \ g$ of $Cu$,the amount of $Ag$ deposited is .............. $g$.

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