A: In a DNA molecule,the proportion of purine | vedclass

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(A) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of purine $(A+G)$ is equal to the amount of pyrimidine $(T+C)$.This is

Vedclass · Accepted Answer

$A$ and $R$ are both true and $R$ is the correct explanation of $A$.

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(A) According to Chargaff's rule,in a double-stranded $DNA$ molecule,the amount of purine $(A+G)$ is equal to the amount of pyrimidine $(T+C)$.This is because,in the $DNA$ double helix,a purine always pairs with a pyrimidine ($A$ pairs with $T$,and $G$ pairs with $C$) due to the specific spatial constraints of the sugar-phosphate backbone.If two purines were to pair,the distance between the strands would be too wide,and if two pyrimidines were to pair,the distance would be too narrow.Therefore,$A$ is true,$R$ is true,and $R$ is the correct explanation for $A$.

$A$: In a $DNA$ molecule,the proportion of purine and pyrimidine bases is equal.
$R$: In $DNA$,two purines or two pyrimidines do not pair opposite each other.

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$A$: In a $DNA$ molecule,the proportion of purine and pyrimidine bases is equal.$R$: In $DNA$,two purines or two pyrimidines do not pair opposite each other.