In a DNA molecule consisting of 28 nucleotide | vedclass

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Question

(B) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of purines $(Adenine + Guanine)$ is equal to the amount of pyrimidin

Vedclass · Accepted Answer

$14$

Vedclass · Answer

(B) According to $Chargaff's$ rule,in a double-stranded $DNA$ molecule,the amount of purines $(Adenine + Guanine)$ is equal to the amount of pyrimidines $(Thymine + Cytosine)$.In any $DNA$ molecule,the total number of nitrogenous bases is equal to the total number of nucleotides.Since the total number of nucleotides is $28$,the total number of nitrogenous bases is also $28$.Because purines and pyrimidines are present in equal proportions ($50\%$ each),the number of purines is calculated as $28 / 2 = 14$.Therefore,the correct answer is $14$.

In a $DNA$ molecule consisting of $28$ nucleotides,what is the number of purine nitrogenous bases?

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