Considering the reaction 3O_2 rightarrow 2O_3 | vedclass

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(B) The reaction $3O_2 \rightarrow 2O_3$ has a positive enthalpy change $(\Delta H > 0)$,which means it is an endothermic process.Since the formation

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Ozone is less stable than oxygen and ozone decomposes to form oxygen immediately.

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(B) The reaction $3O_2 \rightarrow 2O_3$ has a positive enthalpy change $(\Delta H > 0)$,which means it is an endothermic process.Since the formation of $O_3$ from $O_2$ requires energy,$O_3$ is at a higher energy state than $O_2$.According to the principle of stability,substances at higher energy levels are less stable.Therefore,$O_3$ is less stable than $O_2$,and it tends to decompose back into $O_2$ to achieve a more stable,lower-energy state.

Considering the reaction $3O_2 \rightarrow 2O_3$; $\Delta H = +ve$,what can we conclude about the reaction?

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