When 100 cal of heat is supplied to a system | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) According to the first law of thermodynamics,$\Delta U = q + w$. Given: $q = +100 \ cal = 100 	imes 4.184 \ J \approx 418.4 \ J$ (Heat supplied t

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(D) According to the first law of thermodynamics,$\Delta U = q + w$. Given: $q = +100 \ cal = 100 	imes 4.184 \ J \approx 418.4 \ J$ (Heat supplied to the system is positive). Work done by the system is $w = -300 \ J$ (Work done by the system is negative). Therefore,$\Delta U = 418.4 - 300 = 118.4 \ J$. Rounding to the nearest integer provided in the options,$\Delta U = 120 \ J$.

When $100 \ cal$ of heat is supplied to a system,the work done by the system is $300 \ J$. The change in internal energy of the system is ..... $J$.

Similar Questions

$A$ sample of liquid in a thermally insulated container (a calorimeter) is stirred for $2 \ hr$ by a mechanical linkage to a motor in the surroundings. For this process:

The first law of thermodynamics for an isothermal process is:

The reaction in which $\Delta H > \Delta U$ is

If $\Delta H$ is the change in enthalpy and $\Delta E$ is the change in internal energy accompanying a gaseous reaction,which of the following is true?

Identify the reaction for which $\Delta H \neq \Delta E$ :

Vedclass Test Series

Exam Paper Generator

Online Exam Module