The heat of neutralization of $HCl$ by $NaOH$ is $-57.3 \, kJ/mol$. If the heat of neutralization of $HCN$ by $NaOH$ is $-12.1 \, kJ/mol$,then the enthalpy of dissociation of $HCN$ is $...... \, kJ$.

  • A
    $45.2$
  • B
    $-45.2$
  • C
    $69.4$
  • D
    $-69.4$

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