What is the percentage of nitrogen in urea (i | vedclass

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(B) The chemical formula of urea is $NH_2CONH_2$. The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ g/mol$. There are $2$ nitro

Vedclass · Accepted Answer

$46.67$

Vedclass · Answer

(B) The chemical formula of urea is $NH_2CONH_2$. The molar mass of urea is $(2 	imes 14) + (4 	imes 1) + 12 + 16 = 60 \ g/mol$. There are $2$ nitrogen atoms in one molecule of urea. The mass of nitrogen in $1 \ mol$ of urea is $2 	imes 14 = 28 \ g$. The percentage of nitrogen is calculated as: $	ext{Percentage of N} = \frac{	ext{Mass of N}}{	ext{Molar mass of urea}} 	imes 100 = \frac{28}{60} 	imes 100 = 46.67\%$.

What is the percentage of nitrogen in urea (in $\%$)?

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