The vapor density of a metal chloride is 77. | vedclass

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(D) The molecular weight of the metal chloride is $M = 2 	imes 	ext{V.D.} = 2 	imes 77 = 154$.Let the valency of the metal be $x$. The formula of t

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$12$

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(D) The molecular weight of the metal chloride is $M = 2 	imes 	ext{V.D.} = 2 	imes 77 = 154$.Let the valency of the metal be $x$. The formula of the metal chloride is $MCl_x$.The molecular weight is given by $M = 	ext{Equivalent weight of metal} + 	ext{Equivalent weight of chlorine} 	imes x$.$154 = 3 + 35.5x$.$151 = 35.5x$.$x = \frac{151}{35.5} \approx 4.25$.Since valency must be an integer,we check the calculation. If the equivalent weight is $3$,and we assume the formula is $MCl_3$,then $M = 3 + 35.5 	imes 3 = 3 + 106.5 = 109.5$. If $MCl_4$,$M = 3 + 35.5 	imes 4 = 145$. If $MCl_4$ is the closest,the atomic weight $A_w = E 	imes x = 3 	imes 4 = 12$.

List-$I$ (Substance)	List-$II$ (Equivalent weight)
$A. Na_2CO_3$	$I. M/5$
$B. KMnO_4 / H^+$	$II. M/3$
$C. K_2Cr_2O_7 / H^+$	$III. M/2$
$D. KMnO_4 / H_2O$	$IV. M/6$

The vapor density of a metal chloride is $77$. If the equivalent weight of the metal is $3$,what is its atomic weight?

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