If $0.5 \ mol$ of $BaCl_2$ is mixed with $0.1 \ mol$ of $Na_3PO_4$,what is the maximum number of moles of $Ba_3(PO_4)_2$ formed?

If $0.50 \ mol$ of $CaCl_2$ is mixed with $0.20 \ mol$ of $Na_3PO_4$,the maximum number of moles of $Ca_3(PO_4)_2$ which can be formed,is

$NH_3$ is produced according to the following reaction: $N_{2(g)} + 3H_{2(g)} \rightarrow 2NH_{3(g)}$. In an experiment,$0.25 \ mol$ of $NH_3$ is formed when $0.5 \ mol$ of $N_2$ is reacted with $0.5 \ mol$ of $H_2$. What is the percentage yield (in $\%$)?

Balance the following chemical equations:
$(i)$ $Cu_2S + O_2 \to Cu_2O + SO_2$
$(ii)$ $Ca_3(PO_4)_2 + H_2SO_4 \to Ca(H_2PO_4)_2 + CaSO_4$

When $22.4 \ L$ of $H_{2(g)}$ is mixed with $5.6 \ L$ of $Cl_{2(g)}$,each at $S.T.P.$,the moles of $HCl_{(g)}$ formed after completion of the reaction is closest to $.... \ mol$.

In the reaction: $4A + 2B + 3C \to A_4B_2C_3,$ what will be the number of moles of product formed,starting from $1 \, mole$ of $A, 0.6 \, mole$ of $B$ and $0.72 \, mole$ of $C$?