What is the mass of 1 times 10^{22} molecules | vedclass

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(A) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $M = 63.5 + 32 + (4 	imes 16) + 5 	imes (2 	imes 1 + 16) = 63.5 + 32 + 64 + 90 = 249.5

Vedclass · Accepted Answer

$4.159 \, g$

Vedclass · Answer

(A) The molar mass of $CuSO_4 \cdot 5H_2O$ is calculated as: $M = 63.5 + 32 + (4 	imes 16) + 5 	imes (2 	imes 1 + 16) = 63.5 + 32 + 64 + 90 = 249.5 \, g/mol$. Number of moles $n = \frac{	ext{Number of molecules}}{N_A} = \frac{1 	imes 10^{22}}{6.022 	imes 10^{23}} \approx 0.0166 \, mol$. Mass = $n 	imes M = 0.0166 	imes 249.5 \approx 4.14 \, g$. Given the options,the closest value is $4.159 \, g$.

What is the mass of $1 \times 10^{22}$ molecules of $CuSO_4 \cdot 5H_2O$?

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