Hydrogen peroxide and water contain $5.93\%$ and $11.2\%$ of hydrogen,respectively. Which law is illustrated by this data?

  • A
    Law of Multiple Proportions
  • B
    Law of Definite Proportions
  • C
    Law of Reciprocal Proportions
  • D
    Law of Conservation of Mass

Explore More

Similar Questions

Gay-Lussac's law of gaseous volumes is derived from $.......$.

$A$ box contains some identical red-coloured balls,labelled as $A$,each weighing $2 \ g$. Another box contains identical blue-coloured balls,labelled as $B$,each weighing $5 \ g$. Consider the combinations $AB, AB_2, A_2B$ and $A_2B_3$ and show that the law of multiple proportions is applicable.

Difficult
View Solution

The following data are obtained when dinitrogen and dioxygen react together to form different compounds:
Mass of dinitrogen Mass of dioxygen
$14 \ g$ $16 \ g$
$14 \ g$ $32 \ g$
$28 \ g$ $32 \ g$
$28 \ g$ $80 \ g$

Which law of chemical combination is obeyed by the above experimental data?

$1.7 \, g$ of silver nitrate is dissolved in $100 \, g$ of water. Another $0.585 \, g$ of sodium chloride is dissolved in $100 \, g$ of water and added to the first solution,resulting in a chemical reaction. $1.435 \, g$ of silver chloride and $0.85 \, g$ of sodium nitrate are produced. Which law is followed by the above information?

Two elements $X$ and $Y$ have atomic weights of $14$ and $16$. They form a series of compounds $A, B, C, D$ and $E$ in which for the same amount of element $X$,the amounts of $Y$ are present in the ratio $1 : 2 : 3 : 4 : 5$. If the compound $A$ has $28$ parts by weight of $X$ and $16$ parts by weight of $Y$,then the compound $C$ will have $28$ parts by weight of $X$ and:

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo