After balancing the reaction $Cu + HNO_3 \rightarrow Cu(NO_3)_2 + NO_2 + H_2O$ in an acidic medium,the number of nitrogen atoms,the number of water molecules,and the net charge on the product side are respectively:
- A$3, 2, 0$
- B$6, 3, 0$
- C$4, 2, 2$
- D$4, 2, 0$
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