Which of the following contains the maximum n | vedclass

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(B) To find the number of atoms,we multiply the number of molecules by the number of atoms per molecule ($3$ atoms in $CO_2$).$A$: $6.023 	imes 10^{2

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$22.4 \ L$ of $CO_2$ at $STP$

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(B) To find the number of atoms,we multiply the number of molecules by the number of atoms per molecule ($3$ atoms in $CO_2$).$A$: $6.023 	imes 10^{21}$ molecules of $CO_2$ = $3 	imes 6.023 	imes 10^{21} = 18.069 	imes 10^{21}$ atoms.$B$: $22.4 \ L$ of $CO_2$ at $STP$ is $1 \ mole$. Number of atoms = $1 	imes 6.023 	imes 10^{23} 	imes 3 = 18.069 	imes 10^{23}$ atoms.$C$: $0.44 \ g$ of $CO_2$ = $0.44 \ g / 44 \ g/mol = 0.01 \ mol$. Number of atoms = $0.01 	imes 6.023 	imes 10^{23} 	imes 3 = 1.8069 	imes 10^{22}$ atoms.Comparing the values,$18.069 	imes 10^{23}$ is the largest value.Therefore,option $B$ contains the maximum number of atoms.

Which of the following contains the maximum number of atoms?

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