$0.84 \, g$ of a metal hydride contains $0.04 \, g$ of hydrogen. What is the equivalent mass of the metal?
- A$80$
- B$40$
- C$20$
- D$60$
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$0.45 \ g$ of an acid (mol wt. $= 90$) required $20 \ mL$ of $0.5 \ N$ $KOH$ for complete neutralization. The basicity of the acid is:
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View SolutionOne atomic mass unit $(amu)$ is equal to:
Calculate the atomic mass (average) of chlorine using the following data:
Isotope $\%$ Natural Abundance Molar Mass $(g/mol)$ $^{35}Cl$ $75.77$ $34.9689$ $^{37}Cl$ $24.23$ $36.9659$
(in $u$)
| Isotope | $\%$ Natural Abundance | Molar Mass $(g/mol)$ |
| $^{35}Cl$ | $75.77$ | $34.9689$ |
| $^{37}Cl$ | $24.23$ | $36.9659$ |
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