What is the total number of neutrons present | vedclass

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(C) The molar mass of $NH_3 = 14 + 3 	imes 1 = 17 \ g/mol$. Number of moles of $NH_3 = \frac{1.7 \ g}{17 \ g/mol} = 0.1 \ mol$. In one molecule of $N

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$(N_A / 10) 	imes 7$

Vedclass · Answer

(C) The molar mass of $NH_3 = 14 + 3 	imes 1 = 17 \ g/mol$. Number of moles of $NH_3 = \frac{1.7 \ g}{17 \ g/mol} = 0.1 \ mol$. In one molecule of $NH_3$,the number of neutrons is calculated as: Nitrogen $(^{14}N)$ has $14 - 7 = 7$ neutrons. Hydrogen $(^1H)$ has $1 - 1 = 0$ neutrons. Total neutrons per molecule $= 7 + 3 	imes 0 = 7$. Total number of neutrons $= 	ext{moles} 	imes N_A 	imes 	ext{neutrons per molecule} = 0.1 	imes N_A 	imes 7 = (N_A / 10) 	imes 7$.

What is the total number of neutrons present in $1.7 \ g$ of ammonia $(NH_3)$?

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