Dehydration of cyclohexanol (C_6H_{11}OH) to | vedclass

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Question

(A) The chemical equation for the dehydration of cyclohexanol is: $C_6H_{11}OH \rightarrow C_6H_{10} + H_2O$$1$. Molar mass of cyclohexanol $(C_6H_{11

Vedclass · Accepted Answer

$61.5$

Vedclass · Answer

(A) The chemical equation for the dehydration of cyclohexanol is: $C_6H_{11}OH ightarrow C_6H_{10} + H_2O$$1$. Molar mass of cyclohexanol $(C_6H_{11}OH) = (6 	imes 12) + (12 	imes 1) + 16 = 72 + 12 + 16 = 100 \ g/mol$.$2$. Molar mass of cyclohexene $(C_6H_{10}) = (6 	imes 12) + (10 	imes 1) = 72 + 10 = 82 \ g/mol$.$3$. Moles of cyclohexanol taken $= \frac{100 \ g}{100 \ g/mol} = 1 \ mol$.$4$. Theoretical yield of cyclohexene $= 1 \ mol 	imes 82 \ g/mol = 82 \ g$.$5$. Actual yield with $75\%$ efficiency $= 82 \ g 	imes 0.75 = 61.5 \ g$.

Dehydration of cyclohexanol $(C_6H_{11}OH)$ to cyclohexene $(C_6H_{10})$ gives a yield of $75\%$. If $100 \ g$ of cyclohexanol is dehydrated,what is the mass of the product obtained in grams?

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