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(C) According to the Law of Reciprocal Proportions,if two different elements combine separately with a third element,the ratio in which they do so wil

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Law of Reciprocal Proportions

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(C) According to the Law of Reciprocal Proportions,if two different elements combine separately with a third element,the ratio in which they do so will be the same or a simple multiple of the ratio in which they combine with each other.Here,$A$ combines with $B$ in ratio $1:2$ (or $3:6$ by mass).$A$ combines with $C$ in ratio $6:4$ (or $6:4$ by mass).For a fixed mass of $A$ ($6$ parts),$B$ and $C$ combine in the ratio $3:4$.Since $B$ and $C$ combine in a simple whole number ratio,this follows the Law of Reciprocal Proportions.

Compound	$\% Sn$	$\% O$
$A$	$78.77$	$21.23$
$B$	$88.12$	$11.88$

If element $A$ combines with element $B$ in a ratio of $1:2$ by mass,and element $A$ combines with element $C$ in a ratio of $6:4$ by mass,then by which law do elements $B$ and $C$ combine with each other?

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