How many moles of electrons weigh 1 kg? | vedclass

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Question

(D) The mass of one electron is $m_e = 9.108 	imes 10^{-31} \ kg$. The number of electrons in $1 \ kg$ is $N = \frac{1 \ kg}{9.108 	imes 10^{-31} \

Vedclass · Accepted Answer

$\frac{1}{9.108 	imes 6.022} 	imes 10^{8}$

Vedclass · Answer

(D) The mass of one electron is $m_e = 9.108 	imes 10^{-31} \ kg$. The number of electrons in $1 \ kg$ is $N = \frac{1 \ kg}{9.108 	imes 10^{-31} \ kg} = \frac{1}{9.108} 	imes 10^{31}$. Since $1 \ 	ext{mole} = 6.022 	imes 10^{23}$ electrons,the number of moles is $n = \frac{N}{N_A} = \frac{1 	imes 10^{31}}{9.108 	imes 6.022 	imes 10^{23}}$. Simplifying this,we get $n = \frac{1}{9.108 	imes 6.022} 	imes 10^{8}$ moles.

How many moles of electrons weigh $1 \ kg$?

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