What does the equation $2Al(s) + \frac{3}{2}O_2(g) \to Al_2O_3(s)$ represent?

• A
  $2$ moles of $Al$ react with $3/2$ moles of $O_2$ to form $7/2$ moles of $Al_2O_3$.
• B
  $2$ grams of $Al$ react with $3/2$ grams of $O_2$ to form $1$ mole of $Al_2O_3$.
• C
  $2$ gram moles of $Al$ react with $3/2$ liters of $O_2$ to form $1$ mole of $Al_2O_3$.
• D
  $2$ moles of $Al$ react with $3/2$ moles of $O_2$ to form $1$ mole of $Al_2O_3$.