According to the reaction $6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2$,how many molecules of $CO_2$ are required to obtain $1.8 \ g$ of glucose? (Molar mass of $C_6H_{12}O_6 = 180 \ g \ mol^{-1}$) $(C = 12, H = 1, O = 16)$
- A$0.06 \times 6.022 \times 10^{23}$
- B$0.6 \times 6.022 \times 10^{23}$
- C$60 \times 6.022 \times 10^{23}$
- D$6 \times 6.022 \times 10^{23}$
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