An iron alloy contains 54.7% iron and has a d | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Volume of the block = $10 \, cm 	imes 15 \, cm 	imes 20 \, cm = 3000 \, cm^3$. Mass of the block = $	ext{Volume} 	imes 	ext{Density} = 3000 \

Vedclass · Accepted Answer

$14.41 	imes 10^{25}$

Vedclass · Answer

(C) Volume of the block = $10 \, cm 	imes 15 \, cm 	imes 20 \, cm = 3000 \, cm^3$. Mass of the block = $	ext{Volume} 	imes 	ext{Density} = 3000 \, cm^3 	imes 8.17 \, g \, cm^{-3} = 24510 \, g$. Mass of iron in the block = $\frac{54.7}{100} 	imes 24510 \, g = 13406.97 \, g$. Number of moles of $Fe = \frac{13406.97 \, g}{55.85 \, g \, mol^{-1}} \approx 240.05 \, mol$. Number of $Fe$ atoms = $	ext{moles} 	imes N_A = 240.05 	imes 6.022 	imes 10^{23} \approx 1.445 	imes 10^{26}$. Given the options provided,the closest calculated value is $14.41 	imes 10^{25}$.

An iron alloy contains $54.7\%$ iron and has a density of $8.17 \, g \, cm^{-3}$. What is the number of iron atoms in an alloy block of dimensions $10 \, cm \times 15 \, cm \times 20 \, cm$?

Similar Questions

$A$ $250 \, mL$ solution of sodium carbonate contains $5.3 \, g$ of $Na_2CO_3$. If $10 \, mL$ of this solution is taken and diluted with distilled water to $0.1 \, L$,what will be the concentration of the resulting solution?

What is the weight of $H_2SO_4$ (in $g$) required to completely dissolve $3 \ g$ of magnesium carbonate?

When a hydrated salt,$Na_2SO_4 \cdot nH_2O$,is heated,it loses $56\%$ of its weight and becomes anhydrous. What is the approximate value of $n$?

The volume of $0.1 \ M \ HCl$ required in $mL$ to neutralise $20 \ mL$ of a solution containing $0.106 \ g$ of $Na_2CO_3$ is

$8 \ g$ of $H_2$ and $256 \ g$ of $HI$ are in a $4 \ L$ flask. Calculate their active mass. $(H = 1 \ g \ mol^{-1}, I = 127 \ g \ mol^{-1})$

Vedclass Test Series

Exam Paper Generator

Online Exam Module