If 24 times 10^{23} molecules are removed fro | vedclass

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(A) The molar mass of hydrogen gas $(H_2)$ is $2 \ g/mol$.The initial number of moles is calculated as: $n = \frac{50 \ g}{2 \ g/mol} = 25 \ mol$.The

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$21$

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(A) The molar mass of hydrogen gas $(H_2)$ is $2 \ g/mol$.The initial number of moles is calculated as: $n = \frac{50 \ g}{2 \ g/mol} = 25 \ mol$.The number of moles removed is calculated using Avogadro's number $(N_A = 6 	imes 10^{23} \ mol^{-1})$: $n_{removed} = \frac{24 	imes 10^{23}}{6 	imes 10^{23}} = 4 \ mol$.The remaining moles of hydrogen are: $25 \ mol - 4 \ mol = 21 \ mol$.

If $24 \times 10^{23}$ molecules are removed from $50 \ g$ of hydrogen gas $(H_2)$,how many moles of hydrogen remain?

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