Analysis of an organic compound shows $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula is ....

An organic compound on analysis gives the following data: $C = 57.82 \%$,$H = 3.6 \%$ and the rest is oxygen. Its vapour density is $83$. Calculate its molecular formula.

Complete combustion of $X$ g of an organic compound gave $0.25$ g of $CO_2$ and $0.12$ g of $H_2O$. If the percentage of carbon is $25\%$ and of hydrogen is $4.89\%$, then $X = \_\_\_\_ \times 10^{-3}$ g. (Nearest integer) (Molar mass of $C$, $H$ and $O$ are $12, 1$ and $16$ g mol$^{-1}$ respectively.)

The mass $\%$ of carbon in $C_{57}H_{110}O_6$ is

If $1.24 \ g$ of $P$ is present in a $2.2 \ g$ sample of a compound,identify the empirical formula of the compound (Atomic mass of $P = 31 \ g/mol$,$S = 32 \ g/mol$).

Calculate the mass percent of different elements present in sodium sulphate $(Na_{2}SO_{4})$.