A and B are two parallel conductors carrying | vedclass

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(B) $1$. For the conductors $A$ and $B$: When two parallel conductors carry current in the same direction, they produce magnetic fields that result in

Vedclass · Accepted Answer

There will be attraction between $A$ and $B$, and repulsion between $x$ and $y$.

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(B) $1$. For the conductors $A$ and $B$: When two parallel conductors carry current in the same direction, they produce magnetic fields that result in an attractive force between them. The force per unit length is given by $F/L = \frac{\mu_0 I_1 I_2}{2 \pi d}$. Since the currents are in the same direction, the force is attractive.$2$. For the electron beams $x$ and $y$: Electrons are negatively charged particles. When they move in the same direction, they constitute a current in the opposite direction to their motion. However, because they are both negatively charged, they experience a strong electrostatic repulsive force. While there is a magnetic attractive force between the parallel currents formed by the moving electrons, the electrostatic repulsion between the like charges dominates. Therefore, the net force between two parallel electron beams is repulsive.

List-$I$	List-$II$
$(A)$ Fleming's left hand rule	$(i)$ Direction of induced current
$(B)$ Right hand thumb rule	(ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law	(iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule	(iv) Direction of magnetic lines due to current

$A$ and $B$ are two parallel conductors carrying a current $i$ in the same direction. $x$ and $y$ are two electron beams moving in the same direction as shown in the figure.

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