(A) The total milliequivalents of $HCl$ are: $N \times V = 0.1 \times 100 = 10 \, meq$.The milliequivalents of $NaOH$ added are: $N \times V = 0.2 \ti

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(A) The total milliequivalents of $HCl$ are: $N \times V = 0.1 \times 100 = 10 \, meq$.The milliequivalents of $NaOH$ added are: $N \times V = 0.2 \times 30 = 6 \, meq$.For complete neutralization,the total milliequivalents of base must equal the milliequivalents of acid:$N_{HCl} \times V_{HCl} = (N_{NaOH} \times V_{NaOH}) + (N_{KOH} \times V_{KOH})$Substituting the values:$10 = 6 + (0.25 \times V_{KOH})$$4 = 0.25 \times V_{KOH}$$V_{KOH} = \frac{4}{0.25} = 16 \, mL$.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

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$100 \, mL$ of $0.1 \, N \, HCl$ is neutralized by $0.2 \, N \, NaOH$ solution. After adding $30 \, mL$ of $NaOH$ solution,the neutralization is continued using $0.25 \, N \, KOH$. Calculate the volume of $KOH$ in $mL$ required to complete the neutralization.

A
$16$
B
$32$
C
$35$
D
$70$

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Some Basic Concepts of Chemistry

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Chemical stoichiometry

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$100 \, mL$ of $0.1 \, N \, HCl$ is neutralized by $0.2 \, N \, NaOH$ solution. After adding $30 \, mL$ of $NaOH$ solution,the neutralization is continued using $0.25 \, N \, KOH$. Calculate the volume of $KOH$ in $mL$ required to complete the neutralization.

Similar Questions

Thermite is a mixture of $X$ parts of ferric oxide and $Y$ parts of aluminium powder. What are $X$ and $Y$ respectively?

What is the value of percent atom economy when reactants having a sum of formula weight $78 \ u$ result in the formation of a product with a formula weight of $65 \ u$ (in $\%$)?

What weight of $SO_2$ can be made by burning sulphur in $5.0 \ mol$ of oxygen?

The weight of oxalic acid required to neutralize $100 \, cc$ of a normal solution of $NaOH$ is ........ $gm$.

$100 \ mL$ of $0.1 \ N$ hypo solution is decolourised by the iodine liberated from the addition of $x \ g$ of crystalline copper sulphate to an excess of $KI$. The value of $x$ is ............. $g$ (molecular weight of $CuSO_4 \cdot 5H_2O$ is $250$).

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