Which of the following compounds will give a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $1$. $Pb(NO_3)_2$ reacts with $NaCl$ to form $PbCl_2$ (white precipitate),while $Ba(NO_3)_2$ reacts with $NaCl$ to form $BaCl_2$ (soluble in water

Vedclass · Accepted Answer

$NaCl$

Vedclass · Answer

(A) $1$. $Pb(NO_3)_2$ reacts with $NaCl$ to form $PbCl_2$ (white precipitate),while $Ba(NO_3)_2$ reacts with $NaCl$ to form $BaCl_2$ (soluble in water).$2$. $Pb(NO_3)_2$ reacts with sodium acetate to form lead acetate (soluble),while $Ba(NO_3)_2$ also forms soluble barium acetate.$3$. Sodium nitrate does not form a precipitate with either.$4$. Sodium hydrogen phosphate $(Na_2HPO_4)$ forms precipitates with both $Pb^{2+}$ and $Ba^{2+}$ ions.$5$. Therefore,$NaCl$ is the correct answer as it selectively precipitates $Pb^{2+}$ as $PbCl_2$.

Which of the following compounds will give a precipitate with $Pb(NO_3)_2$ but will not give a precipitate with $Ba(NO_3)_2$?

Similar Questions

Which of the following gives a precipitate with $Pb(NO_3)_2$ but not with $Ba(NO_3)_2$?

$X$ (salt) + $AgNO_3$ $(aq.) \to \underset{(\text{Yellow ppt.})}{Y \downarrow}$ (soluble in excess of $NH_3$ solution). Salt $X$ does not contain:

Explain the brown ring test for nitrate ions.

$A$ reagent consisting of $1$-naphthylamine and sulphanilic acid in acetic acid is used for the detection of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module