(B) When ferric ions $(Fe^{3+})$ react with potassium ferrocyanide $(K_4[Fe(CN)_6])$,they form a deep blue precipitate known as Prussian blue. The che

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) When ferric ions $(Fe^{3+})$ react with potassium ferrocyanide $(K_4[Fe(CN)_6])$,they form a deep blue precipitate known as Prussian blue. The chemical reaction is: $4Fe^{3+} + 3[Fe(CN)_6]^{4-} \rightarrow Fe_4[Fe(CN)_6]_3$ This compound is ferric ferrocyanide,which is responsible for the blue color.

Class 11 Chemistry 8-3.Organic Chemistry : Purification and characterization Chemical analysis of organic compounds

Medium

Which compound is responsible for the formation of a blue precipitate when ferric ions react with a Lassaigne's extract or potassium ferrocyanide solution?

A
$K_4[Fe(CN)_6]$
B
$Fe_4[Fe(CN)_6]_3$
C
$KMnO_4$
D
$Fe(OH)_3$

Explore More

Browse All

Question Bank

All Subjects

Class 11 Questions

Class 11

Chemistry Questions

Chapter

8-3.Organic Chemistry : Purification and characterization

Subtopic

Chemical analysis of organic compounds

Match the organic compounds in column $I$ with the Lassaigne's test results in column $II$ appropriately.

Column $I$ Column $II$

$A$. Aniline $i$. Red colour with $FeCl_3$

$B$. Benzene sulfonic acid $ii$. Violet colour with sodium nitroprusside

$C$. Thiourea $iii$. Blue colour with hot and acidic solution of $FeSO_4$

Column $I$	Column $II$
$A$. Aniline	$i$. Red colour with $FeCl_3$
$B$. Benzene sulfonic acid	$ii$. Violet colour with sodium nitroprusside
$C$. Thiourea	$iii$. Blue colour with hot and acidic solution of $FeSO_4$