(C) When $Na_2O_2$ is added to the mixture,$Fe^{2+}$ is oxidized to $Fe^{3+}$,which precipitates as $Fe(OH)_3$ (brown residue).$Al^{3+}$ forms soluble

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Yellow filtrate and brown residue

(C) When $Na_2O_2$ is added to the mixture,$Fe^{2+}$ is oxidized to $Fe^{3+}$,which precipitates as $Fe(OH)_3$ (brown residue).$Al^{3+}$ forms soluble $[Al(OH)_4]^-$ and $Cr^{3+}$ is oxidized to $CrO_4^{2-}$ (yellow filtrate).Thus,the filtrate is yellow due to the presence of chromate ions,and the residue is brown due to the presence of ferric hydroxide.

Class 12 Chemistry Principles Related to Practical Chemistry Wet Test for Basic Radical

Medium

An aqueous solution containing $FeSO_4$,$Al_2(SO_4)_3$,and chrome alum is treated with $Na_2O_2$ and heated,followed by filtration. The resulting products are:

A
Colorless filtrate and green residue
B
Yellow filtrate and green residue
C
Yellow filtrate and brown residue
D
Green filtrate and brown residue

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Wet Test for Basic Radical

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DifficultJEE MAIN 2013

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An aqueous solution containing $FeSO_4$,$Al_2(SO_4)_3$,and chrome alum is treated with $Na_2O_2$ and heated,followed by filtration. The resulting products are:

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$A$ salt '$A$' which gives a green flame with a Bunsen burner,on reaction with dil. $H_2SO_4$ produces gas $(2)$ and white turbidity $(Z)$. The saturated solution of gas $(2)$ on reaction with $H_2S$ gas produces '$Z$'. Then select the $CORRECT$ statement.

Of the following sulphides,which one is insoluble in dilute acids but soluble in alkalies?

Sodium Carbonate cannot be used in place of $(NH_4)_2CO_3$ for the identification of $Ca^{2+}$,$Ba^{2+}$,and $Sr^{2+}$ ions (in group $V$) during mixture analysis because

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