When CO_2 gas is passed through lime water,it | vedclass

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(B) When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it forms a white precipitate of calcium carbonate $(CaCO_3)$,which makes the solution milky:

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Water-soluble $Ca(HCO_3)_2$ is formed.

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(B) When $CO_2$ is passed through lime water $(Ca(OH)_2)$,it forms a white precipitate of calcium carbonate $(CaCO_3)$,which makes the solution milky:$Ca(OH)_2(aq) + CO_2(g) \rightarrow CaCO_3(s) + H_2O(l)$When excess $CO_2$ is passed,the insoluble $CaCO_3$ reacts with $CO_2$ and water to form calcium bicarbonate $(Ca(HCO_3)_2)$,which is soluble in water,causing the milkiness to disappear:$CaCO_3(s) + H_2O(l) + CO_2(g) \rightarrow Ca(HCO_3)_2(aq)$

When $CO_2$ gas is passed through lime water,it turns milky. On passing excess $CO_2$ gas,the milkiness disappears because:

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