In a face-centered cubic (FCC) lattice,A atom | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In an $FCC$ unit cell,the number of $A$ atoms at the corners is $8 	imes \frac{1}{8} = 1$.Initially,there are $6$ face centers,so the number of $

Vedclass · Accepted Answer

$A_2B_5$

Vedclass · Answer

(B) In an $FCC$ unit cell,the number of $A$ atoms at the corners is $8 	imes \frac{1}{8} = 1$.Initially,there are $6$ face centers,so the number of $B$ atoms is $6 	imes \frac{1}{2} = 3$.After removing one $B$ atom from a face center,the number of $B$ atoms becomes $6 - 1 = 5$ face centers remaining,so the number of $B$ atoms is $5 	imes \frac{1}{2} = \frac{5}{2}$.The ratio of $A:B$ is $1 : \frac{5}{2}$,which simplifies to $2 : 5$.Therefore,the molecular formula is $A_2B_5$.

In a face-centered cubic $(FCC)$ lattice,$A$ atoms are present at the corners and $B$ atoms are present at the face centers. If one $B$ atom is removed from one of the face centers,what will be the molecular formula of the compound?

Similar Questions

An element has a $bcc$ structure with $12.08 \times 10^{23}$ unit cells. What is the total number of atoms in these unit cells?

The coordination number of a metal crystallising in a hexagonal close-packed $(HCP)$ structure is

What is the mass of an $fcc$ unit cell if the mass of one atom of an element is $6 \times 10^{-23} \ g$?

In $CsCl$ structure,the coordination number of $Cs^{+}$ is

Which of the following characteristics is true for $ZnS$ solid?

Vedclass Test Series

Exam Paper Generator

Online Exam Module