In the equation PV = nRT,which of the followi | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The universal gas constant $R$ has different values depending on the units used:$1$. In $SI$ units,$R = 8.314 \, J \, K^{-1} \, mol^{-1}$.$2$. In

Vedclass · Accepted Answer

$8.31 \, L \, atm \, K^{-1} \, mol^{-1}$

Vedclass · Answer

(D) The universal gas constant $R$ has different values depending on the units used:$1$. In $SI$ units,$R = 8.314 \, J \, K^{-1} \, mol^{-1}$.$2$. In $CGS$ units,$1 \, J = 10^7 \, 	ext{ergs}$,so $R = 8.314 	imes 10^7 \, 	ext{ergs} \, K^{-1} \, mol^{-1}$.$3$. Since $1 \, J = 1 \, N \cdot m$ and $1 \, N = 10^5 \, 	ext{dynes}$,$1 \, J = 10^5 \, 	ext{dynes} 	imes 10^2 \, cm = 10^7 \, 	ext{dynes} \cdot cm$. Thus,$8.314 	imes 10^7 \, 	ext{dynes} \cdot cm \, K^{-1} \, mol^{-1}$ is also correct.$4$. In $L \cdot atm$ units,$R = 0.0821 \, L \cdot atm \, K^{-1} \, mol^{-1}$.Therefore,the value $8.31 \, L \cdot atm \, K^{-1} \, mol^{-1}$ is incorrect.

In the equation $PV = nRT$,which of the following is not equal to the numerical value of $R$?

Similar Questions

The $S.I.$ unit of the gas constant $R$ is:

At $300 \ K$,a sample of $3.0 \ g$ of gas $A$ occupies the same volume as $0.2 \ g$ of hydrogen $(H_2)$ at $200 \ K$ at the same pressure. The molar mass of gas $A$ is $...... \ g \ mol^{-1}$ (nearest integer). Assume that the gases behave as ideal gases.

$34.05 \, mL$ of phosphorus vapour weighs $0.0625 \, g$ at $546^{\circ} C$ and $0.1 \, bar$ pressure. What is the molar mass of phosphorus?

$A$ cylinder of $5 \, L$ capacity,filled with air at $NTP$,is connected to another evacuated cylinder of $30 \, L$ capacity. The resultant air pressure in both the cylinders will be .............. $cm$ of $Hg$.

Calculate the volume of gas at $1.25 \ atm$,if the volume occupied by the gas at $1 \ atm$ and at the same temperature is $25 \ mL$. (in $mL$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module