For a non-ideal gas,identify the term in the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The van der Waals equation for $n$ moles of a real gas is given by: $\left( P + \frac{an^2}{V^2} \right)(V - nb) = nRT$. For $1$ mole of gas $(n=1

Vedclass · Accepted Answer

$\left( P + \frac{a}{V^2} \right)$

Vedclass · Answer

(C) The van der Waals equation for $n$ moles of a real gas is given by: $\left( P + \frac{an^2}{V^2} \right)(V - nb) = nRT$. For $1$ mole of gas $(n=1)$,the equation becomes: $\left( P + \frac{a}{V^2} \right)(V - b) = RT$. In this equation,the term $\frac{a}{V^2}$ accounts for the intermolecular forces of attraction between gas molecules. Therefore,the term representing intermolecular forces is $\left( P + \frac{a}{V^2} \right)$.

For a non-ideal gas,identify the term in the van der Waals equation that represents the intermolecular forces.

Similar Questions

When is deviation more in the behaviour of a gas from the ideal gas equation $PV = nRT$?

Gases deviate from the ideal gas behaviour because their molecules

Among the gases $a$,$b$,$c$,$d$,$e$ and $f$,the gases that show only positive deviation from ideal behavior at all pressures in the graph are

At $300 \, K$ temperature and $40 \, atm$ pressure,if one mole of $CO_2$ occupies $0.4 \, L$,then it is:

If $Z$ is the compressibility factor,then for $1 \, \text{mole}$ of a real gas,the van der Waals equation at low pressure can be written as:

Vedclass Test Series

Exam Paper Generator

Online Exam Module